Investigating the depression of a ruler when force is applied

... - 6 14.0 14.0 14.0 0.6+ADw-/p+AD4- +ADw-p+AD4-50CM OVERHANG: +ADw-/p+AD4- +ADw-p+AD4-Mass (N) Measurement 1(cm) Measurement 2 (cm) Avg Overhang (cm, 1dp) Bend (cm)+ADw-br+AD4- 0 13.8 13.8 13.8 0.0+ADw-br+AD4- 1 14.1 14.1 14.1 0.3+ADw-br+AD4- 2 14.4 14.4 14.4 0.6+ADw-br+AD4- 3 14.7 14.6 14.65 0.05 0.85 0.05+ADw-br+AD4- 4 15.1 15.2 15.15 0.05 1.35 0.05+ADw-br+AD4- 5 15.5 15.5 15.5 1.7+ADw-br+AD4- 6 15.9 15.9 15.9 2.1+ADw-/p+AD4- +ADw-p+AD4-80CM OVERHANG:+ADw-/p+AD4- +ADw-p+AD4-Mass (N) Measurement 1(cm) Measurement 2 (cm) Avg Overhang (cm, 1dp) Bend (cm)+ADw-br+AD4- 0 14.0 14.0 14.0 0.0+ADw-br+AD4- 1 15.0 15.0 15.0 1.0+ADw-br+AD4- 2 15.9 15.9 15.9 1.9+ADw-br+AD4- 3 16.9 16.8 16.85 0.05 2.85 0.05+ADw-br+AD4- 4 17.8 17.8 17.8 3.8+ADw-br+AD4- 5 18.7 18.7 18.7 4.7+ADw-br+AD4- 6 19.7 19.7 19.7 5.7+ADw-/p+AD4- +ADw-p+AD4-You can see from these results I have calculated the average depression by finding the average of measurement one and two. As you can see, unfortunately some of the results are between values of 1 MM+ADs- this is inconvenient for me because I did not use a scale accurate enough to record these results as I did not have accurate enough measuring instruments. Therefore, on my graph I will plot my results with error bars 1MM long. On the following pages is my section of evaluating my results. This section is mainly graphs showing, hopefully, result patterns.+ADw-/p+AD4- +ADw-p+AD4-Analysing Evidence/Drawing Conclusions+ADw-/p+AD4- +ADw-p+AD4-To see whether there is a pattern I am going to produce another table, which is below to compare results. Also, on the next page is a graph comparing results to see what shape the lines form. If it is proportional, which I predicted it will be a straight line through the origin.+ADw-/p+AD4- +ADw-p+AD4AJg-nbsp+ADsAJg-nbsp+ADsAJg-nbsp+ADsAJg-nbsp+ADsAJg-nbsp+ADsAJg-nbsp+ADsAJg-nbsp+ADsAJg-nbsp+ADs-Bend-30cm Overhang Bend-50cm Overhang Bend-80cm overhang+ADw-br+AD4- Mass (N) Depression (Cm) Depression ...